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Scope statements will look somewhat di erent for di erent kinds of projects. Let us look at a list of issues we must always address, in any scope statement. Business value. From the business perspective, why are we creating this system What is the value What is the return on investment Crucial issues and needs. What is driving this project And what are the critical, absolute features, deadlines, or cost limitations that we already know, if any Business or consumer functions. What work will the system do What will it not do What kind of work will people do on the system What business functions will be enhanced by the system, and what groups will bene t If the produce or service is for consumers, why will they use it How will they use it What will it do for them What will be the value that customers perceive Scope of change. The project will change or replace an existing product or service. Are we creating an upgrade, that is, signi cant changes to a current model, or are we creating a whole new product or service What will be replaced by the results of our project In a business, what tool or system will they stop using when they start using this

and b = (7p /4,2) Using the formulas for conversion stated earlier in this chapter, we find that the Cartesian equivalents are a = {[2 cos (p /4)],[2 sin (p /4)]} and b = {[2 cos (7p /4)],[2 sin (7p /4)]} From trigonometry, we (hopefully) recall that the cosines and sines of these particular angles have values that are easy to denote, even though they re irrational: cos (p /4) = 21/2/2 sin (p /4) = 21/2/2 cos (7p /4) = 21/2/2 sin (7p /4) = 21/2/2 Substituting these values in the ordered pairs for the Cartesian vectors, we get a = [(2 21/2/2),(2 21/2/2)] = (21/2,21/2) and b = {(2 21/2/2),[(2 ( 21/2/2)]} = (21/2, 21/2) When we add these Cartesian vectors, we obtain a + b = {(21/2 + 21/2),[21/2 + ( 21/2)]} = [(2 21/2),0] Let s call this sum vector c = (xc,yc) Then we have xc = 2 21/2 and yc = 0 Using the Cartesian-to-polar conversion formulas, we get qc = 0 and rc = (xc2 + yc2)1/2 = [(2 21/2)2 + 02]1/2 = 2 21/2

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FIG 12.2. In a stripping column, all the condensables are refluxed, all the noncondensables discharged.

Putting these coordinates into an ordered pair, we derive our final answer as a + b = [0,(2 21/2)] That s the polar sum of our original two polar vectors The first coordinate is the angle in radians The second coordinate is the magnitude in linear units

one For consumers, what products or services (ours, or competitors ) will they stop using if they buy our new product or service Let us look at the di erent forms a scope statement might take, and the di erent additional items, by looking at three very di erent projects: the design of a new advertising campaign, the creation of a new or upgraded computer system, and an audit of a business division. For the advertising campaign, we would identify: The products or services being advertised. The expected increase in sales from the campaign, compared to its cost. Whether we are creating the campaign for new products or services, or for existing ones. Whether we plan to create new names and terms for products, or reorganize product lines. The media we plan to use (television, web sites, e-mail, radio, and so forth). The target audience. The length of the campaign. A sense of what will be done in-house, and what will be done by vendors, and which vendors, if we know.

Polar vector difference When we want to subtract a polar vector from another polar vector, we follow these steps in order:

1 2 3 4 Convert both vectors to Cartesian coordinates Find the Cartesian negative of the second vector Add the first vector to the negative of the second vector the Cartesian way Convert the resultant back to polar coordinates

Once again, imagine that we have a = (qa,ra) and b = (qb,rb) The Cartesian equivalents are (xa,ya) = [(ra cos qa),(ra sin qa)] and (xb,yb) = [(rb cos qb),(rb sin qb)] We find the Cartesian negative of b as b = ( xb, yb) The difference vector a b is therefore a b = a + ( b) = {[(xa + ( xb)],[(ya + ( yb)]} = [(xa xb),(ya yb)] Let s call this difference vector d We can say that d = a b = [(xa xb),(ya yb)] = (xd,yd) We can skip the step where we find the Cartesian negative of the second vector and directly subtract the coordinate values, but we must take special care to keep the vectors and coordinate

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